Question

(ab)⁵ × (ab)¹⁵
(2x+3y)⁶ × (2x+3y)¹⁴
(-xy)² × (-xy)⁷ × (-xy)⁹
памахите пжлс ;-; ​

Answer 1

$(ab)^5(ab)^{15}=(ab)^{5+15}=(ab)^{20}\\\\(2x+3y)^6(2x+3y)^{14}=(2x+3y)^{6+14}=(2x+3y)^{20}\\\\(-xy)^2(-xy)^7(-xy)^9=(-xy)^{2+7+9}=(-xy)^{18}=(xy)^{18}$

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$a^x*a^y=a^{x+y}$