Question

помогите пожалуйста!​

Answer 1

1)$\displaystyle 9y - 14x+ 2 = 0$

$\displaystyle 9y = 14x - 2$

$\displaystyle y = \frac{14x - 2}{9}$

2) при х = 2

$\displaystyle y = \frac{14 \times 2 - 2}{9} = \frac{28 - 2}{9} = \frac{26}{9} = 2.89$

При х = 6

$\displaystyle y = \frac{14 \times 6- 2}{9} = \frac{84 - 2}{9} = \frac{82}{9} = 9.11$