Question

Объясните как такое решать.​

Answer 1

ⁿ√a = a^(1/n)

(a^m)^n = a^(mn)

a^-n = 1/a^n

^ степень

⁷√(¹²√a) = ⁷ˣ¹²√a = ⁸⁴√a

√(⁴²√a) = ²ˣ⁴²√a = ⁸⁴√a

⁶√(⁴√a) = ⁶ˣ⁴√a = ²⁴√a

(22*⁸⁴√a - 8*⁸⁴√a)/2*²⁴√a = 14* ⁸⁴√a / 2*²⁴√a = 7* a^(1/84 - 1/24) = 7*a^(2/168 - 7/168) = 7*a^-5/168 = 7/a^5/168 = 7/¹⁶⁸√a⁵