Question

решите двойное неравенство$-8\leq \frac{7x+2}{2} \ \textless \ 8$

Answer 1

$-8\leq \frac{7x+2}{2}<8\\\frac{7x+2}{2}\geq -8, \frac{7x+2}{2}<8\\x\geq -\frac{18}{7}, x<2$

x∈ $[-\frac{18}{7},2)$