Question

Помогите паааааажалуста дам 15 баллов ​

Answer 1

Объяснение:

Задание 4.11

1).

$\frac{( {13}^{5})^{11} \times ( {13}^{4})^{10} }{ ({13}^{47})^{2} } = \frac{ {13}^{55} \times {13}^{40} }{ {13}^{94} } = \frac{ {13}^{95} }{ {13}^{94} } = {13}^{95 - 94} = {13}^{1} = 13$

2).

$\frac{( {7}^{5})^{6} \times {7}^{27} }{(7^{14})^{4} } = \frac{ {7}^{30} \times {7}^{27} }{ {7}^{56} } = \frac{ {7}^{57} }{ {7}^{56} } = {7}^{1} = 7$

3).

$\frac{( {6}^{8})^{9} \times ( {6}^{4}) ^{5} }{( {6}^{24})^{3} \times ({6}^{3} )^{6} } = \frac{ {6}^{72} \times {6}^{20} }{ {6}^{72} \times {6}^{18} } = \frac{ {6}^{92} }{ {6}^{90} } = {6}^{92 - 90} = {6}^{2} = 36$

4).

$\frac{( {19}^{11})^{7} \times {(19}^{7 })^{2} }{( {19}^{20})^{3} \times {19}^{29} } = \frac{19^{77} \times {19}^{14} }{ {19}^{60} \times {19}^{29} } = \frac{ {19}^{91} }{ {19}^{89} } = {19}^{2} = 361$

5).

$\frac{( {3}^{15})^{5} \times ( {3}^{12}) ^{2} }{(3^{2})^{25} \times (3^{3}) ^{16} } = \frac{ {3}^{75} \times {3}^{24} }{ {3}^{50} \times {3}^{48} } = \frac{ {3}^{99} }{ {3}^{98} } = {3}^{1} = 3$

6).

$\frac{( {2}^{40})^{3} \times ( {2}^{12})^{5} }{( {2}^{45})^{2} \times ( {2}^{11})^{4} } = \frac{ {2}^{120} \times {2}^{60} }{ {2}^{90} \times {2}^{44} } = \frac{ {2}^{180} }{ {2}^{134} } = {2}^{46}$