Question

(с10d6)степень3:(с9)степень3:(d2)степень8 при с=-0,25 и d=4/5​

Answer 1

Ответ:

-0,01

Объяснение:

$\frac{(c {}^{10} d {}^{6} ) {}^{3} }{ (c {}^{9}) {}^{3} } \div (d {}^{2} ) {}^{8} = \frac{ {c}^{30} \times {d}^{18} }{c {}^{27} \times d {}^{16} } = c {}^{3} \times d {}^{2} = ( - 0.25) {}^{3} \times ( \frac{4}{5} ) {}^{2} = ( - \frac{1}{4} ) ( \frac{4}{20} ) {}^{2} = - \frac{1}{4} \times \frac{1}{25} = - \frac{1}{100} = - 0.01$

Answer 2

$(c^{10} d^{6})^{3} : (c^{9})^{3} : (d^{2})^{8} = c^{30}d^{18}:c^{27} :d^{16} =c^{3} d^{2}= (-0.25)^{3}*0.8^{2}=-1/64*16/25=-1/100=-0.01$