Question

Надо росписать !!!!!!!​

Answer 1

Ответ:

$a)\ \ \displaystyle \frac{y^2-16}{4y^2-y^3}=\frac{(y-4)(y+4)}{y^2(4-y)}=-\frac{y+4}{y^2}\\\\\\b)\ \ \frac{a^2-2a+1}{1-a^2}=\frac{(a-1)^2}{-(a-1)(a+1)}=-\frac{a-1}{a+1}=\frac{1-a}{a+1}\\\\\\c)\ \ \frac{m^3+8}{m^2-2m+4}=\frac{(m+2)(m^2-2m+4)}{m^2-2m+4}=m+2\\\\\\d)\ \ \frac{3+3n+3n^2}{n^3-1}=\frac{3\, (1+n+n^2)}{(n-1)(n^2+n+1)}=\frac{3}{n-1}$