Question

Обчисліть 10 sin 30° + 4 cos 120° − √3 tg 60°​

Answer 1

$10 \sin30 {}^{ \circ} + 4 \cos120 {}^{ \circ} - \sqrt{3} \tg60 {}^{ \circ} = 10 \times \dfrac{1}{2} + 4 \times ( - \dfrac{1}{2} ) - \sqrt{3} \times \sqrt{3} = 5 - 2 - 3 = 3 - 3 = \pmb0.$