Question

сор за 7 класс по математике​

Answer 1

Ответ:

1.

а. $6^2 - 3 * 2^3 = 36 - 3*8 = 36 - 24 = 12$

б. $(-1)^3 - 1^0 = -1 - 1 = -2$

2.

a. $(c^5)^3 * c^4 = c^{5*3 + 4} = c^{19}$

b. $\frac{x^2 * x}{x^3} = x^{2 + 1 - 3} = x^0 = 1$

c. $(-2ab)^4 = 16a^4b^4$

3.

b. $\frac{6^{12}}{36*6^9} = \frac{6^{12}}{6^2*6^9} = 6^{12 - (2+9)} = 6^1 = 6$

4.

а. $4.67 * 10^{15}$

b. $2.57 * 10^{-8}$

Answer 2

Ответ:

1. a) $6^{2}-3*2^3=36-3*8=36-24=12$

1. б) $(-1)^3-1^0=-1-1=-2$

2. а) $(c^5)^3*c^4=c^{15}*c^4=c^{15+4}=c^{19}$

2.б) $\frac{x^2*x}{x^3} =\frac{x^{2+1}}{x^3} =\frac{x^3}{x^3} =1$

2.в) $(-2ab)^4=(-2)^4a^4b^4=16a^4b^4$

3. $\frac{6^{12}}{36*6^9} =\frac{6^{12}}{6^2*6^9}=\frac{6^{12}}{6^{2+9}}=\frac{6^{12}}{6^{11}} =6$

4. a) $4670000000000000=4,67*10^{15}$

4.б)  $0,0000000257=2,57*10^{-8}$