Question

Даны функции f(x)=6/x-2x2 и g(x)=4/x-2.
Найдите f(-3)+g(-2)+f(1)

Answer 1

Ответ:

-20

Объяснение:

$f(x)=\frac{6}{x}-2x^2;\; \; \; g(x)=\frac{4}{x}-2\\\\\\f(-3)=\frac{6}{-3}-2(-3)^2=-2-2*9=-2-18=-20\\\\g(-2)=\frac{4}{-2}-2=-2-2=-4\\\\f(1)=\frac{6}{1}-2*1^2=6-2=4\\\\\\f(-3)+g(-2)+f(1)=-20-4+4=-20$