Question

Развяжите уравнение
log2 (8-x) = log2 (x+12)
Плиз,срочно!

Answer 1

Ответ:

x = -2

Объяснение:

log2(8-x) = log2(x+12)

log2(8-x) = log2(x+12), x пренадлежит (-12, 8)

8-x = x+12

-x-x = 12-8

-2x = 4

x = -2, x пренадлежит (-12, 8)

x = -2

Answer 2

Ответ:

x = -2

Объяснение:

$\displaystyle\\log_2(8-x)=log_2(x+12)\\\\\left \{ {\bigg{8-x>0}\atop\bigg {x+12>0}} \atop \bigg{8-x=x+12}} \right. \ \ \ \ \left \{ {\bigg{x<8}\atop\bigg {x>-12}} \atop \bigg{2x=-4}} \right. \ \ \ \ \ \left \{ {\bigg{x<8}\atop\bigg {x>-12}} \atop \bigg{x=-2}} \right.\\\\\\otvet:\ x=-2$