Question

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Answer 1

Ответ:

$7)\ \ \ a+b=2\\\\7a+7b-10=7(a+b)-10=7\cdot 2-10=14-10=4\\\\\\8)\ \ (49)^8:(7^3)^5=(7^2)^8:7^{15}=7^{16}:7^{15}=7^1=7\\\\0,2^3\cdot 10^3-8^2\cdot 0,5^2=\dfrac{2^3}{10^3}\cdot 10^3-2^6\cdot \dfrac{1}{2^2}=2^3-2^4=2^3\cdot (1-2)=8\cdot (-1)=-8\\\\\\9)\ \ -11^6=-1\cdot 11^6=-(11^6)<0\\\\(-11)^6=\Big(-1\cdot 11\Big)^6=(-1)^6\cdot 11^6=+1\cdot 11^6=11^6>0\\\\-11^6<(-11)^6$

$b)\ \ \Big(-\dfrac{3}{22}\Big)^4=(-1)^4\cdot \Big(\dfrac{3}{22}\Big)^4=+1\cdot \dfrac{3^4}{22^4}=\dfrac{81}{234256}>0\\\\(-10)^9=(-1)^9\cdot 10^9=-1\cdot 10^9=-(10^9)<0\\\\\Big(-\dfrac{3}{22}\Big)^4>(-10)^9\\\\\\c)\ \ \ \ \ 3^{44}\ \vee \ 4^{33}\\\\{}\ \ \ \ (3^4)^{11}\ \vee \ (4^3)^{11}\\\\{}\ \ \ \ \ 81^{11}\ \vee \ 64^{11}\\\\81>64\ \ \ \Rightarrow \ \ \ 81^{11}\ >\ 64^{11}$