Question

(2⁷×2‐⁴)³÷16×32 комектемындерш​

Answer 1

Ответ:

$({2}^{3}) ^{3} - {2}^{4} \times {2}^{5} = {2}^{9} - {2}^{9} = 0$

Answer 2

Решение и ответ:

$\displaystyle \[{\left( {{2^7} \cdot {2^{-4}}} \right)^3} \div 16 \cdot 32={\left( {{2^{7+( -4)}}} \right)^3} \div {2^4} \cdot {2^5}={\left( {{2^{7-4}}} \right)^3} \div {2^{4+5}} ={\left( {{2^3}} \right)^3} \div {2^9}={2^{3 \cdot 3}} \div {2^9}={2^9} \div {2^9}={2^{9 -9}}={2^0}=\boxed{1}$

$16=2 \cdot 2 \cdot 2 \cdot 2={2^4}$

$32=2 \cdot 2 \cdot 2 \cdot 2 \cdot 2={2^5}$