Question

3m -1 / 4 -m + 2 m + 3 / m -4

Answer 1

$\dfrac{3m-1}{4-m} +\dfrac{2m+3}{m-4}=\dfrac{3m-1}{4-m} -\dfrac{2m+3}{4-m} =\dfrac{3m-1-2m-3}{4-m}=\\\\=\dfrac{m-4}{4-m}=-\dfrac{m-4}{m-4}=\boxed{-1}$