Question

2x²+x-3/x²-2x+1
Допоможіть будь ласка

Answer 1

$\dfrac{2x^{2}+x-3 }{x^{2}-2x+1 } \\\\\\1) \ 2x^{2} +x-3=0\\\\D=1^{2}-4\cdot2\cdot(-3)=1+24=25=5^{2} \\\\x_{1}=\dfrac{-1-5}{4} =\dfrac{-6}{4}=-1,5\\\\x_{2}=\dfrac{-1+5}{4} =\dfrac{4}{4} =1\\\\\boxed{2x^{2} +x-3=2(x+1,5)(x-1)}\\\\\\2) \ x^{2}-2x+1=0\\\\(x-1)^{2} =0\\\\x-1=0\\\\x_{1,2} =1\\\\\boxed{x^{2}-2x+1=(x-1)(x-1)} \\\\\\3) \ \dfrac{2x^{2}+x-3 }{x^{2}-2x+1 }=\dfrac{2(x+1,5)(x-1)}{(x-1)(x-1)}=\dfrac{2(x+1,5)}{x-1} =\boxed{\dfrac{2x+3}{x-1}}$