Question

Здравствуйте, помогите пожалуйста с алгеброй:<
7 класс
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Answer 1

Ответ:

$8\frac{2}{3} x^{3} -16ay^{2} +9ay^{2} -9x^{3} =-\frac{1}{3} x^{3} -7ay^{2}$

$27a^{2} z-24,89a^{2} z+3\frac{1}{5} y^{2} -15y^{2} =2,11a^{2} z-11,8y^{2}$

$3,12ab+7\frac{5}{6} m^{3} -4\frac{1}{6} m^{3} +16,82ab=20ab+3\frac{2}{3} m^{3}$

$19,2x^{2} -30\frac{1}{9} kt+31kt-20x^{2} =-0,8x^{2}+\frac{8}{9} kt$

Объяснение:

1)

$8\frac{2}{3} x^{3} -16ay^{2} +9ay^{2} -9x^{3} =-9x^{3} +8\frac{2}{3} x^{3} -16ay^{2} +9ay^{2} =\\\\=-(9x^{3} -8\frac{2}{3} x^{3} )-(16ay^{2} -9ay^{2} )=-\frac{1}{3} x^{3} -7ay^{2}$

2)

$27a^{2} z-24,89a^{2} z+3\frac{1}{5} y^{2} -15y^{2} =(27a^{2} z-24,89a^{2} z)+(3\frac{1}{5} y^{2} -15y^{2} )=\\\\=2,11a^{2} z-(15y^{2}-3\frac{1}{5} y^{2} )=2,11a^{2} z-11\frac{4}{5} y^{2} =2,11a^{2} z-11,8y^{2}$

3)

$3,12ab+7\frac{5}{6} m^{3} -4\frac{1}{6} m^{3} +16,82ab= (3,12ab+16,82ab)+(7\frac{5}{6} m^{3} -4\frac{1}{6} m^{3}) =\\\\=20ab+3\frac{4}{6} m^{3}=20ab+3\frac{2}{3} m^{3}$

4)

$19,2x^{2} -30\frac{1}{9} kt+31kt-20x^{2} =19,2x^{2}-20x^{2} -30\frac{1}{9} kt+31kt=\\\\= (19,2x^{2}-20x^{2})+(31kt-30\frac{1}{9} kt)=-0,8x^{2}+\frac{8}{9} kt$