Question

НАРОД ДАМ 70 БАЛЛОВ ХЕЛП
Решите систему неравенств:

Answer 1

Ответ:

Объяснение:

$\displaystyle\bf\\\left \{ {{19x-2x^2-42>0} \atop {(x^2-9)(x-4)(1-x)\leq 0}} \right. \ \ \ \ \left \{ {{2x^2-19x+42<0} \atop {(x+3)(x-3)(x-4)(x-1)\geq 0}} \right. \\\\\\\left \{ {{2x^2-12x-7x+42<0} \atop {(x+3)(x-3)(x-4)(x-1)\geq 0}} \right. \\\\\\\left \{ {{2x(x-6)-7(x-6)<0} \atop {(x+3)(x-3)(x-4)(x-1)\geq 0}} \right. \\\\\\\left \{ {{(x-6)(2x-7)<0} \atop {(x+3)(x-3)(x-4)(x-1)\geq 0}} \right.$

$\displaystyle\\\left \{ {{++++++++++++++++(3,5)-----(6)+++>x} \atop {+++[-3]----[1]+++[3]---[4]+++++>x}} \right.\\\\\\\left \{ {{x\in(3,5;\ 6)} \atop {x\in(-\infty;-3]\cup[1;3]\cup[4;+\infty)}} \right. \\\\\\Otvet: x\in[4;6)$