Question

Система уравнения 4х+у=-10 ниже под ним log3 (3у-х)=2

Answer 1

$left { {{4x + y = -10} atop {log_3(3y-x) = 2}} right.$

$left { {{4x + y = -10} atop {3y - x = 3^2}} right.$

$left { {{x = 3y - 9} atop {l12y - 36 + y = -10}} right.$

$left { {{x = 3y - 9} atop {l13y = 26}} right.$

$left { {{y = 2} atop {x = -3}} right.$  

Answer 2

4x+y=-10

log₃(3y-x)=2

 

y=-10-4x

3²=3y-x

 

9=3(-10-4x)-x

9=-30-12x-x

-13x=39

x=-3

 

y=-10-4*(-3)

y=-10+12

y=2