Question

ПОМОГИТЕ ПЛИЗ СКОРО В ШКОЛУ НЕ УСПЕЮ РЕШИТЬ​

Answer 1

3.

$\frac{x - 6y^{2} }{2y} + 3y = \frac{x}{2y} - 3y + 3y = \frac{x}{2y}$

при х = -8, у = 0,1:

$\frac{ - 8}{2 \times 0.1} = \frac{ - 8}{0.2} = - 40$

4.

$\frac{2}{x - 4} - \frac{x + 8}{ {x}^{2} - 16 } - \frac{1}{x} = \\ \frac{2}{x - 4} - \frac{x + 8}{(x - 4)(x + 4)} - \frac{1}{x} = \\ \frac{2( {x}^{2} + 4x) - x(x + 8) - (x - 4)(x + 4)}{x(x - 4)(x + 4)} = \\ \frac{2 {x}^{2} + 8x - {x}^{2} - 8x - {x}^{2} + 16 }{x(x - 4)(x + 4)} = \\ \frac{16}{x(x - 4)(x + 4)}$