Question

Срочно помогите, там, y=sin2xcos6x+cos2xsin6x

Answer 1

Ответ:   $T=\dfrac{\pi }{4}$  .

$y=sin2x\, cos6x+cos2x\, sin6x\\\\y=sin(2x+6x)\\\\y=sin8x\\\\T(sin8x)=\dfrac{T(sinx)}{8}=\dfrac{2\pi }{8}=\dfrac{\pi}{4}$