Question

Помогите решить пример поэтапно

Answer 1

Ответ:

Надо x÷y×1=2 xy и мы умножаем на 2

Answer 2

$(\frac{x}{y^{2}+xy }+\frac{x-y}{x^{2} -xy} ):(\frac{y^{2} }{x^{3}-xy^{2} } +\frac{1}{x-y} )\\1) \frac{x}{y^{2}+xy }+\frac{x-y}{x^{2} -xy} =\frac{x}{y(y+x) }+\frac{x-y}{x(x -y)} =\frac{x*x*(x-y)}{xy(y+x)(x-y)} +\frac{(x-y)*y*(y+x)}{xy(y+x)(x-y)}=\frac{x^{2}(x-y)+y(x-y)(x+y)}{xy(y+x)(x-y)} =\frac{x^{3}-x^{2}y+y(x^{2}-y^{2})}{xy(y+x)(x-y)} =\frac{x^{3}-x^{2}y+x^{2}y-y^{3}}{xy(y+x)(x-y)}=\frac{x^{3}-y^{3}}{xy(y+x)(x-y)}=\frac{(x-y)(x^{2}+xy+y^{2})}{xy(y+x)(x-y)} =\frac{x^{2}+xy+y^{2}}{xy(y+x)}$$2) \frac{y^{2} }{x^{3}-xy^{2} } +\frac{1}{x-y}=\frac{y^{2} }{x(x^{2}-y^{2}) } +\frac{1}{x-y}=\frac{y^{2} }{x(x-y)(x+y) } +\frac{1}{x-y}=\frac{y^{2} +1*x*(x+y)}{x(x-y)(x+y)} =\frac{y^{2} +x^{2}+xy}{x(x-y)(x+y)}\\3)\frac{x^{2}+xy+y^{2}}{xy(x+y)}:\frac{y^{2} +x^{2}+xy}{x(x-y)(x+y)}=\frac{x^{2}+xy+y^{2}}{xy(x+y)}*\frac{x(x-y)(x+y)}{y^{2} +x^{2}+xy} =\frac{(x^{2}+xy+y^{2})*x(x-y)(x+y)}{xy(x+y)*(y^{2} +x^{2}+xy)} =\frac{x-y}{y}$