Question

решите уравнение пожалуйста​

Answer 1

$\displaystyle\huge\bf \frac{x {}^{24} }{x {}^{26} } \cdot \frac{x {}^{10} }{x {}^{7} } = 19 \\ \bf \huge\dfrac{1}{x {}^{26 - 24} } \cdot \: x {}^{10 - 7} = 19 \\ \bf \huge \dfrac{1}{x {}^{2} } \cdot \: x {}^{3} = 19 \\ \bf \huge \: x {}^{3 - 2} = 19 \\ \bf \huge \: \boxed{ \bf \: x = 19}.$