Question

Помогите с алгеброй пжжж

Answer 1

Ответ:

1)

$\frac{8x - 24}{x - 3} = \frac{8(x - 3)}{x - 3} = 8$

2)

$\frac{y {}^{4} + 3 {y}^{4} + 12 }{y {}^{4} + 3 } = \frac{y {}^{4}(1 + 3) + 12 }{y {}^{4} + 3} = \frac{4y {}^{4} + 12}{y {}^{4} + 3 } = \frac{4(y {}^{4} + 3) }{y {}^{4} + 3 } = 4$