Question

поможіть поможіть поможіть поможіть ​

Answer 1

Ответ:

$( - \frac{2}{5} xy {}^{2} ) {}^{2} \times ( - 2 \frac{1}{2} x {}^{2} y) {}^{3} =\left(-\frac{2}{5}\right)^{2}x^{2}\left(y^{2}\right)^{2}\left(\left(-\frac{2\times 2+1}{2}\right)x^{2}y\right)^{3} =\left(-\frac{2}{5}\right)^{2}x^{2}y^{4}\left(\left(-\frac{2\times 2+1}{2}\right)x^{2}y\right)^{3} =\frac{4}{25}x^{2}y^{4}\left(\left(-\frac{2\times 2+1}{2}\right)x^{2}y\right)^{3} =\frac{4}{25}x^{2}y^{4}\left(\left(-\frac{4+1}{2}\right)x^{2}y\right)^{3} =\frac{4}{25}x^{2}y^{4}\left(-\frac{5}{2}x^{2}y\right)^{3} =\frac{4}{25}x^{2}y^{4}\left(-\frac{5}{2}\right)^{3}\left(x^{2}\right)^{3}y^{3} =\frac{4}{25}x^{2}y^{4}\left(-\frac{5}{2}\right)^{3}x^{6}y^{3} =\frac{4}{25}x^{2}y^{4}\left(-\frac{125}{8}\right)x^{6}y^{3} =-\frac{5}{2}x^{2}y^{4}x^{6}y^{3} =-\frac{5}{2}x^{8}y^{4}y^{3} =-\frac{5}{2}x^{8}y^{7}$