Question

Как это решить?
a²+3b²-4ab
—————— =
a³-a²b

Answer 1

$\frac{a^{2}+3b^{2} -4ab }{a^{3} -a^{2}b } = \frac{a^{2}-4ab+3b^{2} }{a^{2}(a-b) } = \frac{a^{2} -ab-3ab+3b^{2} }{a^{2}(a-b) } = \frac{a(a-b)-3b(a-b)}{a^{2}(a-b)} = \frac{(a-3b)(a-b)}{a^{2}(a-b)} = \\\\=\frac{a-3b}{a^{2} }$