Question

6x^2-5x+1=0 решите плиз

Answer 1

$6x^2-5x+1=0\\a=6, b = -5, c=1\\D=b^2-4ac=(-5)^2-4*6*1=25-24=1\\x_1=\frac{-b+\sqrt{D} }{2a}=\frac{-(-5)+\sqrt{1} }{2*6}=\frac{5+1}{12}=\frac{6}{12}=\frac{1}{2} \\x_2=\frac{-b-\sqrt{D} }{2a}=\frac{-(-5)-\sqrt{1} }{2*6}=\frac{5-1}{12}=\frac{4}{12}=\frac{1}{3}$

Ответ: $\frac{1}{3} ,\frac{1}{2}$

Answer 2

6x²-5x+1=0; D=(-5)²-4*6*1=25-24=1=1²; x_{1}=(5-1)/(2*6)=4/12=1/3; x_{2}=(5+1)/(2*6)=6/12=1/2. Ответ: ⅓; ½.