Question

Даны две функции g(x)=3x^2-2x f(x)=2x+1

Answer 1

$g(x)=3x^{2} -2x\\\\f(x)=2x+1\\\\\\g\Big((f(x)\Big)=3(2x+1)^{2} -2\cdot(2x+1)=3(4x^{2} +4x+1)-4x-2=\\\\=12x^{2} +12x+3-4x-2=\boxed{12x^{2} +8x+1}$