Question

ПОМОГИТЕ УЗТЕСТРУ 7 КЛАСС АЛГЕБРА

Answer 1

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Answer 2

$\Big(\dfrac{3}{7} \Big)^{7} \cdot\Big(2\dfrac{1}{3} \Big)^{8} =\Big(\dfrac{3}{7} \Big)^{7} \cdot\Big(\dfrac{7}{3} \Big)^{8} =\dfrac{3^{7} \cdot7^{8} }{7^{7} \cdot3^{8} } =\boxed{\dfrac{7}{3} }=\boxed{2\dfrac{1}{3} }$