Question

найдите корни уравнения​

Answer 1

$arctan(x^{3}-27x-\sqrt{3})=-\frac{\pi }{3} \\x^{3}-27x-\sqrt{3}=tan(-\frac{\pi }{3})\\x^{3}-27x-\sqrt{3}=-\sqrt{3}\\x^{3}-27x=0\\x(x^{2} -27)=0\\x=0,x^{2} -27=0\\x_{1}=-3\sqrt{3},x_{2}=0,x_{3}=3\sqrt{3}$