Question

СРОЧНО!!!ПОЖАЛУЙСТА!!​

Answer 1

( а )

$\displaystyle\\\frac{x}{\sqrt{3} } =\frac{x}{\sqrt{3} }*\frac{\sqrt{3} }{\sqrt{3} } = \frac{x\sqrt{3} }{\sqrt{3^2} } =\frac{x\sqrt{3} }{3}$

( б )

$\displaystyle\\\frac{2}{\sqrt{3}- y} =\frac{2}{\sqrt{3}-y } *\frac{\sqrt{3}+y }{\sqrt{3}+y } =\frac{2(\sqrt{3}+y) }{(\sqrt{3}-y)(\sqrt{3}+y) } =\frac{2\sqrt{3}+2y }{\sqrt{3^2}-y^2 }= =\frac{2\sqrt{3}+2y }{3-y^2}$