Question

(1/3)^-1 -(1/8)^0 +(3/4)^2×16=​

Answer 1

${( \frac{1}{3} )}^{ - 1} - {( \frac{1}{8}) }^{0} + {( \frac{3}{4}) }^{2} \times 16$

$3 - {( \frac{1}{8} )}^{0} + {( \frac{3}{4}) }^{2} \times 16$

$3 - 1 + {( \frac{3}{4} )}^{2} \times 16$

$3 - 1 + \frac{9}{16} \times 16$

$3 - 1 + 9$

$11$