Question

Помогите пожалуйста с заданием!! Срочно нужно!! ​

Answer 1

$1)4 \sqrt{2} + \sqrt{50} - \sqrt{18} = 4 \sqrt{2} + 5 \sqrt{2} - 3\sqrt{2} = 6 \sqrt{2} \\ 2) \sqrt{3} (2 \sqrt{3} + \sqrt{12} ) = 2 \sqrt{9} + \sqrt{36} = 6 + 6 = 12 \\ 3)( \sqrt{5} - 2 {)}^{2} = \sqrt{ {5}^{2} } - 4 \sqrt{5} + 4 = 5 - 4\sqrt{5} + 4 = 9 - 4 \sqrt{5} \\ 4)( \sqrt{3} - \sqrt{2} )( \sqrt{3} + \sqrt{2} ) = \sqrt{9} - \sqrt{4} = 3 - 2 = 1 \\ 5) \frac{1}{2} \sqrt{12} - 2 \sqrt{27} + \sqrt{75} = \sqrt{3} - 6 \sqrt{3} + 5 \sqrt{3} = 0 \\ 6)3 \sqrt{2} (5 \sqrt{2} - \sqrt{32} ) = 15 \sqrt{4} - 3\sqrt{64} = 30 - 24 = 6 \\ 7)(4 - 5 \sqrt{2} {)}^{2} = 16 - 40 \sqrt{2} + 25 \sqrt{4} = 16 - 40 \sqrt{2} + 50 = 66 - 40 \sqrt{2} \\ 8)( \sqrt{7} - 2 \sqrt{3} )( \sqrt{7} + 2 \sqrt{3} ) = \sqrt{49} - 4 \sqrt{9} = 7 - 12 = - 5$