Question

решить целое уравнение

Answer 1

$\frac{x^{2}}{27}+\frac{x}{3}=\frac{x+9}{3}\\\\\frac{x^{2} }{27}+\frac{9x}{27}-\frac{9(x+9)}{27}=0\\\\\frac{x^{2}+9x-9x-81}{27}=0\\\\x^{2} -81=0\\(x-9)(x+9)=0\\x=9\\x=-9$

Ответ:

$x=9\\x=-9$