Question

Решите, пожалуйста, номер 3), 4), 5) по алгебре!!!​

Answer 1

$3) \frac{\sqrt{x}-9 }{ \sqrt[4]{x}+3 }=\frac{(\sqrt[4]{x}+3)(\sqrt[4]{x}-3)}{\sqrt[4]{x}+3}=\sqrt[4]{x}-3 \\\\4)\frac{\sqrt[3]{x}+\sqrt[6]{x} }{x+\sqrt[6]{x^5} } =\frac{\sqrt[6]{x} (\sqrt[6]{x}+1)}{\sqrt[6]{x^5}(\sqrt[6]{x}+1)} =\frac{\sqrt[6]{x} }{\sqrt[6]{x^5}} =\frac{1}{\sqrt[6]{x^4} } =\frac{1}{\sqrt[3]{x^2} }$

$5)\frac{\sqrt[8]{2a^3}-\sqrt[8]{8a} }{\sqrt[8]{a}-\sqrt[8]{2} } =\frac{\sqrt[8]{2a}( \sqrt[8]{a^2}-\sqrt[8]{4} ) }{\sqrt[8]{a}-\sqrt[8]{2} }=\frac{\sqrt[8]{2a}( \sqrt[8]{a}-\sqrt[8]{2} )( \sqrt[8]{a}+\sqrt[8]{2} ) }{\sqrt[8]{a}-\sqrt[8]{2}}=\sqrt[8]{2a}( \sqrt[8]{a}+\sqrt[8]{2} )$