Question

2 1+2x ** + 3x 10 X-3 5 x? -9​

Answer 1

Ответ:

$\displaystyle \frac{1+2x}{x-3}-\frac{x^2+3x}{5}\cdot \frac{10}{x^2-9}=\frac{1+2x}{x-3}-\frac{x\, (x+3)}{5}\cdot \frac{10}{(x-3)(x+3)}=\\\\\\=\frac{1+2x}{x-3}-\frac{2x}{x-3}=\frac{1+2x-2x}{x-3}=\frac{1}{x-3}$