Question

срочно!!!!!!!!!!!!!!!​

Answer 1

$\dfrac{x^2+1}{(x-3)^2}-\dfrac{5x}{(x-3)^2}+\dfrac{8-x}{(x-3)^2}=1\\\\\\\dfrac{x^2+1-5x+8-x}{(x-3)^2}=1\\\\\\\dfrac{x^2-6x+9}{(x-3)^2}=1\\\\\\\dfrac{(x-3)^2}{(x-3)^2}=1\\\\\\1=1$