Question

Пожалуста помогите решить ​

Answer 1

$1)0,4^3=(\frac{2}{5})^3=\frac{8}{125}\\2)(-6)^4=6^4=6\cdot6\cdot6\cdot6=1296\\3)(-25)^1=-25\\4)(-0,1)^5=(-\frac{1}{10})^5=-\frac{1}{100000}\\5)-(1\frac{1}{3})^2=-(\frac{4}{3})^2=-\frac{16}{9}\\6)(-\frac{1}{3})^4=(\frac{1}{3})^4=\frac{1^4}{3^4}=\frac{1}{81}$