Question

Решите cos П+ctg2П/6+sin(-П/6)

Answer 1

$\displaystyle\bf\\Cos\pi+Ctg^{2} \frac{\pi }{6} +Sin\Big(-\frac{\pi }{6} \Big)=Cos\pi+Ctg^{2} \frac{\pi }{6} -Sin\frac{\pi }{6} =\\\\\\=-1+(\sqrt{3} )^{2} -\frac{1}{2} =-1+3-0,5=1,5$