Question

найдите корень уравнения:
пжпжпж ПОМОГИТЕ....​

Answer 1

$\displaystyle\bf1)~\frac{2}{5}-y=-\frac{3}{7};\\\bf-y=-\frac{3}{7}-\frac{2}{5};\\\bf-y=-\frac{15+14}{35};\\\bf-y=-\frac{29}{35};\\\bf~y=\frac{29}{35}.$

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$\displaystyle\tt~a+4\frac{5}{12}=-3\frac{1}{9};\\\tt~a+\frac{53}{12}=-\frac{28}{9};\\\tt~a=-\frac{28}{9} -\frac{53}{12} ;\\\tt~a=-\frac{112+159}{36};\\\tt~a=-\frac{271}{36} =-7\frac{19}{36} .$

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$\displaystyle\sf~b+2\frac{4}{11} =\frac{2}{3} ;\\\sf~b+\frac{26}{11} =\frac{2}{3} ;\\\sf~b=\frac{2}{3} -\frac{26}{11} ;\\\sf~b=\frac{22-78}{33} ;\\\sf~b=\frac{-56}{33} =-\frac{56}{33} =-1\frac{23}{33} .$

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$\displaystyle1\frac{4}{15} -x=2\frac{5}{8} ;\\\frac{19}{15} -x=\frac{21}{8} ;\\-x=\frac{21}{8} -\frac{19}{15} ;\\-x=\frac{315-152}{120} ;\\-x=\frac{163}{120} ;\\x=-\frac{163}{120} =-1\frac{43}{120} .$