Question

скоротить дріб
........​

Answer 1

$\displaystyle\bf\\1)\\\\\frac{\sqrt{x} -9}{\sqrt[4]{x} +3} =\frac{(\sqrt[4]{x} )^{2}-3^{2}}{\sqrt[4]{x} +3} =\frac{(\sqrt[4]{x} +3)(\sqrt[4]{x} -3)}{\sqrt[4]{x} +3} =\sqrt[4]{x} -3\\\\\\2)\\\\\frac{x^{\frac{1}{3} }-2x^{\frac{1}{6} } y^{\frac{1}{6} } +y^{\frac{1}{3} }}{x^{\frac{1}{2} } y^{\frac{1}{3} }-x^{\frac{1}{3} } y^{\frac{1}{2} }} =\frac{(x^{\frac{1}{6} } -y^{\frac{1}{6} })^{2} }{x^{\frac{1}{3} }y^{\frac{1}{3} } (x^\frac{1}{6} -y^{\frac{1}{6} }) } }=$

$\displaystyle\bf\\=\frac{x^{\frac{1}{6} }-y^{\frac{1}{6} }}{x^{\frac{1}{3} } y^{\frac{1}{3} } }$