Question

Срочно!!! Помогите решить :(

Answer 1

$\displaystyle\bf\\\Big(\frac{m-n}{m^{2} +mn} +\frac{1}{m} \Big):\frac{m}{m+n} =\Big(\frac{m-n}{m(m +n)} +\frac{1}{m} \Big)\cdot\frac{m+n}{m} =\\\\\\=\frac{m-n+m+n}{m(m+n)} \cdot\frac{m+n}{m} =\frac{2m}{m\cdot m} =\frac{2}{m} \\\\\\m=-0,25\\\\\\\frac{2}{m} =\frac{2}{-0,25} =-8$