Question

36^(log6 5) + 10^(1-lg2) - 8^(log2 3) срочно​

Answer 1

Ответ:

Объяснение:

 36^(log6 5) + 10^(1-lg2) - 8^(log2 3)=

=(6^(log6 5))² + 10/(10^lg2) - (2(log2 3))³=

=5² + (10/2) - 3³=25+5-27=30-27=3