Question

Срочно!!!!!!!!!!:;((((((пожалуста

Answer 1

$y = 8x {}^{5} + 3x - 5 \\ y' = \frac{d}{dx} (8x {}^{5} + 3x - 5) \\ y ' = \frac{d}{dx} (8x {}^{5} ) + \frac{d}{dx} (3x) - \frac{d}{dx} (5) \\ y' = 8 \times 5x {}^{4} + 3 = 0 \\ y' = 40x {}^{4} + 3$