Question

помогите решить !!! $\left \{ {3(x+y)=39} \atop {x+3=y}} \right.$ $\left \{ {{6x-y=-1} \atop {3x+2y=-3}} \right.$

Answer 1

$\displaystyle\bf\\1)\\\\\left \{ {{3(x+y)=39} \atop {x+3=y}} \right. \\\\\\+\left \{ {{x+y=13} \atop {x-y=-3}} \right. \\--------\\2x=10\\\\x=5\\\\y=x+3=5+3=8\\\\Otvet:(5 \ ; \ 8)\\\\\\2)\\\\\left \{ {{6x-y=-1}| \ \cdot 2 \atop {3x+2y=-3}} \right. \\\\\\\left \{ {{12x-2y=-2} \atop {3x+2y=-3}} \right. \\---------\\15x=-5\\\\x=-\frac{1}{3} \\\\y=6x+1=6\cdot\Big(-\frac{1}{3} \Big)+1=-2+1=-1\\\\Otvet:\Big(-\frac{1}{3} \ ; \ -1\Big)$

Answer 2

Объяснение:

Решение будет во вложении