Question

Решите 3 - 4 задания пожалуйста!!!

Answer 1

3) f(x) = 2√2*x - sin(4x)
f' = 2√2 - 4cos(4x) = 0
4cos(4x) = 2√2
cos(4x) = √2/2
4x = +-π/4 + 2πk
x = +-π/16 + πk/2
4) f' = 0.5*x^2 - x ≥ 0
x*(0.5x - 1) ≥ 0
x ≤ 0, x ≥ 2

Answer 2

Спасибо=)