• Предмет: Математика
  • Автор: robloxbest2002
  • Вопрос задан 6 лет назад

помогите пожалуйста111111

Приложения:

gulfairuzazamat: подажди 5-10 мин
robloxbest2002: ок

Ответы

Ответ дал: bbbapho
1

1. Выполните действия:

1)

7 \frac{7}{9}  - 4 \frac{1}{12}  + 2 \frac{3}{4}  = 7 \frac{28}{36}  - 4 \frac{3}{36}  + 2 \frac{27}{36}  = (7 +  \frac{28}{36})  - (4 +  \frac{3}{36} ) + (2 +  \frac{27}{36} ) = 7 +  \frac{28}{36}  - 4 -  \frac{3}{36}  + 2 +  \frac{27}{36}  = 5 +  \frac{28 - 3 + 27}{36}  = 5 +  \frac{52}{36}  = 5 +  \frac{13}{9}  =5 + 1 \frac{4}{9}  =  5 + 1 +  \frac{4}{9}  = 6 +  \frac{4}{9}  = 6 \frac{4}{9}

2)

17 \frac{2}{3}  - 6 \frac{1}{36}  + 4 \frac{3}{8}  = 17 \frac{48}{72}  - 6 \frac{2}{72}  + 4 \frac{27}{72}  = (17 +  \frac{48}{72} ) - (6 +  \frac{2}{72} ) + (4  +  \frac{27}{72} ) = 17 +  \frac{48}{72}  - 6 -  \frac{2}{72}  + 4 +  \frac{27}{72}  = 15 +  \frac{48 - 2 + 27}{72}  = 15  +  \frac{73}{72}  = 15 + 1 \frac{1}{72}  = 15 + 1 +  \frac{1}{72}  = 16 \frac{1}{72}

3)

10 \frac{9}{16}  - (3 \frac{11}{12}  + 4 \frac{4}{9} ) = 10 \frac{9}{16}  - 3 \frac{11}{12}  - 4 \frac{4}{9}  = 10 \frac{81}{144}  - 3 \frac{132}{144}  - 4 \frac{64}{144}  = (10 +  \frac{81}{144} ) - (3 +  \frac{132}{144} ) - (4 +  \frac{64}{144} ) = 10 +  \frac{81}{144}  - 3 -  \frac{132}{144}  - 4 -  \frac{64}{144}  = 3 +  \frac{81 - 132 - 64}{144}  = 3 + (  - \frac{ 115}{144} ) = 3 -  \frac{115}{144}  = 2 +  \frac{144}{144}  -  \frac{115}{144}  = 2 +  \frac{144 - 115}{144}  = 2 +  \frac{29}{144}  = 2 \frac{29}{144}

4)

(20 - 7 \frac{23}{36} ) - (14 \frac{4}{27}  - 6 \frac{1}{18} ) = (19 \frac{36}{36}  - 7 \frac{23}{36} ) - (14 \frac{8}{54}  - 6 \frac{3}{54} ) = (19 +  \frac{36}{36}  - 7 -  \frac{23}{36} ) - (14 +  \frac{8}{54}  - 6 -  \frac{3}{54} ) = (12 +  \frac{36 - 23}{36} ) - (8 +  \frac{8 - 3}{54} ) = (12 +  \frac{13}{36} ) - (8 +  \frac{5}{54} ) = 12 +  \frac{39}{108}  - 8 -  \frac{10}{108}  = 4 +  \frac{36 - 10}{108}  = 4 +  \frac{26}{108}  = 4 +  \frac{13}{54}  = 4 \frac{13}{54}

2. Найдите значение выражения:

1)

(9 \frac{3}{7}  + 2 \frac{9}{16} ) - 5 \frac{3}{7}  = 9 \frac{3}{7}  + 2 \frac{9}{16}  - 5 \frac{3}{7}  = (9 \frac{3}{7}  - 5 \frac{3}{7} ) + 2 \frac{9}{16}  = (9 +   \frac{3}{7}  - 5 -  \frac{3}{7} ) + 2 \frac{9}{16}  = 4 + 2 \frac{9}{16}  = 4 + 2 +  \frac{9}{16}  = 6 +  \frac{9}{16}  = 6 \frac{9}{16}

2)

10 \frac{5}{14}  - (3 \frac{5}{14}  + 2 \frac{9}{34} ) = 10 \frac{5}{14}  - 3 \frac{5}{14}  - 2 \frac{9}{34}  = (10 \frac{5}{14}  - 3 \frac{5}{14} ) - 2 \frac{9}{34}  = (10 +  \frac{5}{14}  - 3 -  \frac{5}{14} ) - 2 \frac{9}{34}  = 7  - 2 \frac{9}{34}  = 6 \frac{34}{34}  - 2 \frac{9}{34}  = 6 +  \frac{34}{34}  - 2 -  \frac{9}{34}  = 4 +  \frac{34 - 9}{34}  = 4 +  \frac{25}{34}  = 4 \frac{25}{34}

3. Упростите выражение:

1)

 \frac{3a}{8b}  -  \frac{a}{5b}  =  \frac{3}{8}  \times  \frac{a}{b}  -  \frac{1}{5}  \times  \frac{a}{b}  =  \frac{a}{b} ( \frac{3}{8}  -  \frac{1}{5} ) =  \frac{a}{b} ( \frac{15}{40}  -  \frac{8}{40} ) =  \frac{a}{b}  \times  \frac{7}{40}  =  \frac{7a}{40b}

2)

 \frac{4m}{9n}  +  \frac{5m}{12n}  =  \frac{4}{9}  \times  \frac{m}{n}  +  \frac{5}{12}  \times  \frac{m}{n}  =  \frac{m}{n} ( \frac{4}{9}  +  \frac{5}{12} ) =  \frac{m}{n} ( \frac{16}{36}  +  \frac{15}{36} ) =  \frac{m}{n}  \times  \frac{31}{36}  =  \frac{31m}{36n}

3)

 \frac{7x}{6y}  -  \frac{4x}{15y}  =  \frac{7}{6}  \times  \frac{x}{y}  -  \frac{4}{15}  \times  \frac{x}{y}  =  \frac{x}{y} ( \frac{7}{6}  -  \frac{4}{15} ) =  \frac{x}{y} ( \frac{35}{30}  -  \frac{8}{30} ) =  \frac{x}{y}  \times  \frac{27}{30}  =  \frac{x}{y}  \times  \frac{9}{10}  =  \frac{9x}{10y}

4. Решить уравнения:

1)

(x +  \frac{5}{12} ) -  \frac{9}{20}  =  \frac{11}{15}

x =  \frac{11}{15}  -  \frac{5}{12}  +  \frac{9}{20}

x =  \frac{44}{60}  -  \frac{25}{60}  +  \frac{27}{60}

x =  \frac{46}{60}

x =  \frac{23}{30}

2)

(x -  \frac{7}{15} ) +  \frac{5}{8}  =  \frac{17}{24}

x =  \frac{17}{24}  +  \frac{7}{15}  -  \frac{5}{8}

x =   \frac{85}{120}  +  \frac{56}{120}  -  \frac{75}{120}

x =  \frac{66}{120}

x =  \frac{11}{20}

3)

 \frac{4}{5}  - (x +  \frac{1}{60} ) =  \frac{2}{3}

 \frac{4}{5}  - x -  \frac{1}{60}  =  \frac{2}{3}

x =  \frac{4}{5}  -  \frac{1}{60}  -  \frac{2}{3}

x =  \frac{48}{60}  -  \frac{1}{60}  -  \frac{40}{60}

x =  \frac{7}{60}

4)

4 \frac{3}{4}  - (x - 2 \frac{5}{8} ) = 3 \frac{5}{6}

4 \frac{3}{4}  - x + 2 \frac{5}{8}  = 3 \frac{5}{6}

x = 4 \frac{3}{4}  + 2 \frac{5}{8}  - 3 \frac{5}{6}

x = 4 +  \frac{3}{4}  + 2 +  \frac{5}{8}  - 3 -  \frac{5}{6}

x = 3 + ( \frac{3}{4}  +  \frac{5}{8}  -  \frac{5}{6} )

x = 3 + ( \frac{18}{24}  +  \frac{15}{24}  -  \frac{20}{24} )

x = 3 +  \frac{13}{24}

x = 3 \frac{13}{24}

5)

9 \frac{9}{28}  - (4 \frac{5}{21}  - x) = 6 \frac{2}{7}

9 \frac{9}{28}  - 4 \frac{5}{21}  + x = 6 \frac{2}{7}

x = 6 \frac{2}{7}  - 9 \frac{9}{28}  + 4 \frac{5}{21}

x = 6 +  \frac{2}{7}  - 9 -  \frac{9}{28}  + 4 +  \frac{5}{21}

x = 1 + ( \frac{2}{7}  -  \frac{9}{28}  +  \frac{5}{21} )

x = 1 + ( \frac{24}{84}  -  \frac{27}{84}  +  \frac{20}{84} )

x = 1 +  \frac{17}{84}

x = 1 \frac{17}{84}

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