Question

помогите с 6 и 7 заданием

Answer 1

$\displaystyle\bf\\6) \ \frac{2x^{2} }{x-5} -2x=\frac{2x^{2} -2x\cdot(x-5)}{x-5} =\frac{2x^{2} -2x^{2} +10x}{x-5} =\frac{10x}{x-5} \\\\\\7) \ \frac{y^{2} -10y+25}{5y-1} :\Big(5-y\Big)^{2} =\frac{(y-5)^{2} }{5y-1} \cdot\frac{1}{(y-5)^{2} } =\frac{1}{5y-1}$