Question

Будь ласка 1 і 2
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Answer 1

$\displaystyle\bf\\1) \ \frac{a-3}{6-2a} =\frac{a-3}{2(3-a)} =-\frac{a-3}{2(a-3)} =-\frac{1}{2}=-0,5 \\\\\\2) \ \frac{a^{2} -4}{a-2} =\frac{(a-2)(a+2)}{a-2} =a+2\\\\a=-1,5\\\\a+2=-1,5+2=0,5\\\\\\3) \ \frac{a^{3}-1 }{a^{2} +a+1} =\frac{(a-1)(a^{2}+a+1) }{a^{2} +a+1}=a-1\\\\a=-1,5\\\\a-1=-1,5-1=-2,5$