Question

помогите пожалуйста​

Answer 1

Ответ:

$1)3x {}^{2} + 32x + 80 = 0 \\ d = 1024 - 4 \times 3 \times 80 = \\ 1024 - 960 = 64 = {8}^{2} \\ x1 = \frac{ - 32 - 8}{6} = - \frac{40}{6} = - 6 \frac{4}{6} \\ = - 6 \frac{2}{3}$

$x2 = \frac{ - 32 + 8}{6} = - \frac{24}{6} = - 4$

$2)2x {}^{2} + 9x - 486 = 0 \\ d = 81 + 4 \times 2 \times 486 = \\ = 81 + 3888 = 3969 = {63}^{2} \\ x1 = \frac{ - 9 - 63}{4} = - \frac{72}{4} = - 18 \\ x2 = \frac{ - 9 + 63}{4} = \frac{54}{4} = 13.5$

$3)3 {x}^{2} - 6x + 3 = 0 \div 3 \\ {x}^{2} - 2x + 1 = 0 \\ d = 4 - 4 = 0 \\ x = \frac{6 + 0}{2} = \frac{6}{2} = 3$

$4) {9x}^{2} + 6x + 1 = 0 \\ d = 36 - 36 = 0 \\ x = \frac{ - 6 + 0}{18} - \frac{6}{18} = - \frac{1}{3}$

Answer 2

Вот это ответ на первый Премер на остальные незнаю