Question

2^ 1 / (2 log81 от 2)

Answer 1

$\displaystyle\bf\\2^{\frac{1}{2\log_{81} 2} }=2^{\frac{1}{\log_{81} 2^{2} } } =2^{\frac{1}{\log_{81} 4} }=2^{\log_{4} 81} =2^{\log_{2} 9} =9$